X^2+8x=960

Solution for X^2+8x=960 equation:

X^2+8X=960

We move all terms to the left:

X^2+8X-(960)=0

a = 1; b = 8; c = -960;
Δ = b2-4ac
Δ = 82-4·1·(-960)
Δ = 3904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3904}=\sqrt{64*61}=\sqrt{64}*\sqrt{61}=8\sqrt{61}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{61}}{2*1}=\frac{-8-8\sqrt{61}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{61}}{2*1}=\frac{-8+8\sqrt{61}}{2}
$